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Conditional union with several conditions

I have three individual lists containing numbers:
a = [8,10,12,4,5]
b = [5,6,7,8,9]
c = [4,5,6,7,8]

As you can see, these lists have common entries (4 and 5 in a, 5,6 and 5,6 in b, and 4,5,6,7 and 4,5,6,7 in c.
I would like to combine a, b, and c into a single list, such that, for each list:

The numbers to be kept are those which are common to every list

So, for example:
4 will be discarded in list a, 5 and 6 in list b, and 4,5,6,7 and 4,5,6,7 in list c.
I am trying to find the most efficient way of doing this.
I know that a simple solution would be to iterate over a, b, and c and look for items that are present in all 3 lists, then discard them, but I was wondering if there was an efficient way to do this without using 3 nested loops.

A:

You can try this:
import itertools
lst = [8, 10, 12, 4, 5]
lst2 = [5, 6, 7, 8, 9]
lst3 = [4, 5, 6, 7, 8]
res = []
for k in lst:
for i in lst2:
for j in lst3:
if i == k and j == k:
continue
else:

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